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4834 No. 4834 edit
Name:Lion
Age:19-20 years
Gender:Lion
159 posts omitted. Last 50 shown. Expand all images
>> No. 5001 edit
>>4999
Look at that baka.
>> No. 5002 edit
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5002
>>5000
No, that was a good one, you don't have to make another.

>>5001
Look at that baka.
>> No. 5003 edit
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5003
>>4999
But I can't oversee it, it being true or otherwise. I'm just upset at how stupid that guy is.
>> No. 5004 edit
>that patch
Oh wow, why.
>> No. 5005 edit
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5005
>>5004
Patch? To the Umineko fighting game?
>> No. 5006 edit
>>5004

Why?
>> No. 5007 edit
>>5005
Someone else already finished the voice patch for umineko ep1. It would be usually a very good thing, but Kinjo was working on that one.
>> No. 5008 edit
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5008
>>5007
Oh, that. Were the missing files for Jessica ever found?
>> No. 5009 edit
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5009
Meta and Kinjo take turns rolling a 6-sided die. Once either person rolls a 6 the game is over. Meta rolls first, if he doesn't roll a 6, Kinjo rolls the die, if he doesn't roll a 6, Meta rolls again. They continue taking turns until one of them rolls a 6.

Kinjo rolls a 6 before Meta.

What is the probability Kinjo rolled the 6 on his second turn?

Note: Decimals are rounded to the hundred-thousandths place.

A. 0.45455
B. (5/6)*(1/6)
C. 125/1296
D. 0.21219
E. None of the above
>> No. 5010 edit
>>5009
E.

The answer's 1/6.
>> No. 5011 edit
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5011
>>5010
This question is for Kinjo's game.
>> No. 5012 edit
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5012
>>4999
Riddles? What riddles?
>> No. 5013 edit
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5013
>>5009
My eyes just kind of glaze over at probability problems.
>> No. 5014 edit
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5014
>>5009
Who did the first roll?
And futhermore, do furniture knows what a die is?
>> No. 5015 edit
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5015
>>5013
Punctuate the following so that it makes sense:

James while John had had had had had had had had had had had a better effect on the teacher
>> No. 5016 edit
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5016
>>5011
I know it is, but I know about the probability for one roll of the dice being a certain amount won't change just because of a previous value. Every roll has the same probability.
>> No. 5018 edit
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5018
>>5009
Tch, probability...! I'd say B.
>>5012
It's for my game. Each seacat is going to make a riddle and it'll be used in-game. So you can make one too, John!
>> No. 5019 edit
>>5009
C
>> No. 5020 edit
>his second turn
Never mind my other post. It's C.
>> No. 5021 edit
>>5009
I'm with Sakutarou. E.
>> No. 5022 edit
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5022
>>5016
When talking about cumulative effects I believe they do. Or they never didn't?
>> No. 5023 edit
>>5022
It said what are the odds of one specific roll being a certain value, not several rolls.
>> No. 5024 edit
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5024
>>5015
That is a LOT of hads.

James, while John had had "had," had had "had had;" "had had" had had a better effect on the teacher. It's kind of crazy until you figure out what the sentence is trying to say.
>> No. 5025 edit
>>5016
The probability that Kinjo rolled the 6 specifically on the fourth turn of the game rather than earlier or later isn't the same as just rolling a 6 whenever. You've already gone through three consecutive rolls that weren't 6.
>> No. 5026 edit
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5026
>>5024
>;"
>> No. 5027 edit
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5027
>>5026
I know commas always go inside, but I honestly forgot the rule for semicolons. Since I hardly use them.
>> No. 5028 edit
To clarify on the probability one
Meta rolls a non-6, 5/6 chance of occurring
Kinjo rolles a non-6, 5/6 chance
Meta rolls another non-6
Kinjo rolls a 6, 1/6 chance

5/6 times 5/6 times 5/6 times 1/6.
>> No. 5029 edit
>>5025
But when that roll happens, it's still just 1/6.
>> No. 5031 edit
>>5029
I believe the problem is than the game ends if someone rolls a 6. So the past actions affect the probability of getting a 6 in the fourth roll.
>> No. 5032 edit
>>5027
I think all punctuation marks except for periods and commas depend on whether they're part of the quotation or part of the sentence itself.
>> No. 5033 edit
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5033
>>5016
http://en.wikipedia.org/wiki/Conditional_probability

>>5018
I'll try come up with a good one, then.
>> No. 5034 edit
>>5029
Do you know of the monty hall problem?

>Suppose you're on a game show, and you're given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what's behind the doors, opens another door, say No. 3, which has a goat. He then says to you, "Do you want to pick door No. 2?" Is it to your advantage to switch your choice?
>> No. 5035 edit
>>5031
It honestly shouldn't. I could flip a coin ten times, I first get 2 tails, then 8 heads. If I flipped the coin, most people assume since I get keeping heads, I have a better chance at getting tails. But I don't.

It is still 50/50, and it will always be 50/50 unless I cheat someway.
>> No. 5036 edit
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5036
.....
>> No. 5037 edit
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5037
>>5034
I will blow up your ship and kill the crew.
>> No. 5038 edit
>>5035
The question isn't asking you what the chance of a coin flip is. It's asking you what the chance is of the game ending on that certain turn. If you said the chance of it ending on the 1000th turn was also 1/6, would you be right?
>> No. 5039 edit
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5039
>>5037
You seem upset.
>> No. 5040 edit
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5040
>>5032
It also seems to vary between American and British English. For example, I believe American English says that commas ALWAYS go inside, while British English is conditional.
>> No. 5041 edit
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5041
>>5034
No, but it doesn't really change which door is the right one, now does it?
>> No. 5042 edit
Gwah, I can't come up with no riddle!
>> No. 5043 edit
>>5035
The problem isn't telling us that the first ten coin tosses were "certainly" two heads and then eight tails. To use your example again, it's asking you something like "what's the probability that the tenth flip is the very first tails result?"
>> No. 5044 edit
>>5038
yes
>> No. 5045 edit
>>5038
But it is the same, only change 2 options to 6 for a dice. You still always have a 16.6 chance, or 1/6 chance at getting it each roll. Because you could easily roll a '1' ten times in a roll, but would that make it so you won't roll another '1' next time. Nope, it will still be 16.6% percent.
>> No. 5046 edit
>>5041
No, but there are three possible outcomes.
1 - You chose the door with goat A, switching will get you the car
2 - You chose the door with goat B, switching will get you the car
3 - You chose the door with the car, switching will get you a goat

2/3 chance of getting the car if you switch, 1/3 you chose it from the start.
>> No. 5047 edit
>>5045
We're not looking at probability just concerning the single roll. We're looking up probability concerning the entire game. It should be obvious when I put it this way: if you flip a coin 1000 times, is the chance that you will get your first tails result on your 1000th try 50%?
>> No. 5048 edit
>>5045
It's very easy to test. Here's an experiment.

Toss a coin 3 times.
- If and only if it shows two tails and then one heads on the fifth toss, count it as a success.
- In other words:
- - If it shows heads before the 3rd toss, count it as a failure.
- - If it shows 3 tails, count it as a failure.

Repeat the set of three tosses until you have a good number of successes and failures marked. (Normally, around 30, but that's too much. Maybe 10.)
See if the results show a 50% chance of success (getting the first heads on the third try and nowhere else).
>> No. 5049 edit
>>5046
But I didn't pick the door with Goat B. Goat B was in Door 3. The only doors left are one with a goat and one with a car.
>> No. 5050 edit
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5050
>>5040
But yes, I found the appropriate semi-colon rule, and I messed that one up. But the sentence should be otherwise correct.
>> No. 5052 edit
New tea party.
>>5051
>> No. 5058 edit
>>5049
You're ignoring where the problem started and treating it as a new problem between only the two doors, when I've laid out what the possibilities could be.

But I don't want to argue with you over a problem that's famous for causing denial in the face of all evidence. Kind of like 0.99...=1.
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